36=-4.9t^2+28t+14

Solution for 36=-4.9t^2+28t+14 equation:

36=-4.9t^2+28t+14

We move all terms to the left:

36-(-4.9t^2+28t+14)=0

We get rid of parentheses

4.9t^2-28t-14+36=0

We add all the numbers together, and all the variables

4.9t^2-28t+22=0

a = 4.9; b = -28; c = +22;
Δ = b2-4ac
Δ = -282-4·4.9·22
Δ = 352.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-\sqrt{352.8}}{2*4.9}=\frac{28-\sqrt{352.8}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+\sqrt{352.8}}{2*4.9}=\frac{28+\sqrt{352.8}}{9.8}
$